Bryans, Mahut and Herbert Set For Miami SF

One of the greatest doubles teams of all-time will meet one of the hottest on the ATP World Tour in the Miami Open semi-finals.

Bob Bryan and Mike Bryan, who have won 109 tour-level titles, will face Pierre-Hugues Herbert and Nicolas Mahut, the Indian Wells doubles champions, in the semi-finals on Thursday.

The Frenchmen survived their countrymen on Wednesday, knocking out Jeremy Chardy and Fabrice Martin 6-7(5), 7-6(5), 10-7. Herbert and Mahut now have won eight consecutive matches.

The Bryans beat the Australian wild-card team of Omar Jasika and John-Patrick Smith 7-6(5), 6-3 on Wednesday. The Americans feasted on the Australians’ second serves, winning 58 per cent of those points. The future Hall of Famers are looking to become the first team to win three consecutive Miami titles since Todd Woodbridge and Mark Woodforde from 1995-97. The Bryans also won Miami titles in 2007-08.

The other semi-final match will feature Treat Huey of the Philippines and Max Mirnyi of Belarus against South African Raven Klaasen and American Rajeev Ram. Huey and Mirnyi beat Americans John Isner and Nicholas Monroe 6-1, 7-5. Klaasen and Ram beat Philipp Petzschner and Alexander Peya 7-6(5), 5-7, 10-7.