Medvedev Moves One Step Closer To Brisbane Final
Medvedev Moves One Step Closer To Brisbane Final
Russian awaits the winner of Tsonga and De Minaur
Daniil Medvedev is one step closer to a second ATP Tour final on Australian soil, almost 12 months on from capturing his first title at the Sydney International. The fourth-seeded Russian kept his nerve on Friday to defeat 2016 champion and fifth seed Milos Raonic of Canada 6-7(2), 6-3, 6-4 in two hours and nine minutes at the Brisbane International.
Medvedev withstood 29 aces from Raonic, saved all eight break points he faced – including three set points at 4-5 in the first set – and struck 12 aces to advance to the semi-finals, where he will face France’s Jo-Wilfried Tsonga or seventh seed Alex de Minaur of Australia.
Raonic had three set points at 5-4, with Medvedev serving at 0/40, but the Russian fought off all three and forced a tie-break. There, however, Raonic dominated to take the opener.
Medvedev secured the first break of the match, though, in the second game of the second set and cruised to even the quarter-final with an ace. The 22-year-old needed to bide his time until the ninth game of the decider when he broke Raonic, who won 82 per cent of his first-service points.
In addition to the Sydney title (d. de Minaur), World No. 16 Medvedev also lifted ATP Tour trophies in 2018 at the Winston-Salem Open (d. Johnson) and the Rakuten Japan Open Tennis Championships (d. Nishikori). Raonic, 28, has compiled 30+ wins in seven of the past eight seasons.
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